the mass of steam at hundred degree centigrade is to be passed into water of mass hundred grams at 20 degree centigrade to raise its temperature by 5 degrees centigrade is (a)0.4g (b)0.8g
Share
the mass of steam at hundred degree centigrade is to be passed into water of mass hundred grams at 20 degree centigrade to raise its temperature by 5 degrees centigrade is (a)0.4g (b)0.8g
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
The mass of steam : 0.8 g
Explanation:
To find the quantity of heat required to raise the temperature by 5 degree
Q = m c Δθ
here m is the mass of water , c is its specific heat and Δθ is the rise in temperature
Here m = 100 gm , c = 1 cal , Δθ = 5 degree
Thus Q = 100 x 1 x 5 = 500 cal
When the steam is made to pass through water , it condenses to water and heat is released . In this case , there is no change in temperature
Thus Q = m L , here L is the latent heat of steam and m is the mass
Thus m = Q/L = 500/542 = 0.8 g approx
Here 542 cal is the latent heat of vaporization for water
Answer:
the above answer is perfectly correct