the mean of 6 numbers is 11. the first 4 numbers are 6,8,10,and 12 .find the last two numbers, if one of them is 2 more than the other..
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the mean of 6 numbers is 11. the first 4 numbers are 6,8,10,and 12 .find the last two numbers, if one of them is 2 more than the other..
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Given :-
Aim :-
Average :-
The average of any number of observations is calculated by using the formula :-
Let the 6 numbers be x,y,z,a,b and c.
According to the question,
The remaining two numbers b and c can be expressed as :-
(As one of the 2 numbers is 2 more than the other)
Substituting the values,
By adding all the constants and variables in the numerator,
By transposing 6 to the RHS (Right Hand Side),
Transposing 38 to the other side, we get :-
By transposing 2,
By reducing to the lowest terms,
Hence the 2 numbers are :-
Verification :-
By substituting the values of b and b+2 as 14 and 16 respectively, let us verify the Equation.
Adding all the numbers in the numerator,
By cancelling, we get
LHS = RHS
Therefore verified
Verified answer
Answer:
14,28
Step-by-step explanation:
given the numbers are 6,8,10,12,
and their mean is equal to 11
let the numbers be 2+x,x
so,6+8+10+12+2+x+x/6=11
38+x+x/6=11
38+2x/6=11
38+2x=66
2x=66-38=28
2x=28
x=14
2x28