the number of electrons in 11.5g Na+ is
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Answer:
given mass = 11.5 molar mass of Na =23 no. of moles of Na = 11.5/23 = 1/2 %
no. of atoms = no. of moles x avagadro no. = 1/2 x 6.022 × 10^23 = 3.022 × 10 ^23 atoms
Answer:
In 23 g of Na the number of atoms=6.022×10²³
In one gram of Na the number of electons =6.022×10²³/23
In 11.5 g of Na the number of atoms
=6.022×10²³×11.5/23
=6.022×10²²×5
=30.11×10²² mole
=3.011×10²³
The answer is 3.011×10²³ number of atoms or mole
Hope this helps you friend