the number of first increasd by 20% and then it's decreased by 20% .find the net increase or decrease percent?
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the number of first increasd by 20% and then it's decreased by 20% .find the net increase or decrease percent?
If you don't know this answers plz skip do not write incorrect answer
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Answer:
let the number be x
1st Case, increased by 20%
X + X*20/100
6X/5
2nd case, decreased by 20%
6X/5 - 6X/5 * 20/100
6X/5 - 6X/25
24X/25
Net Change = X - 24X/25
= X/25
so net decrease percentage = ((X/25) / X) *100
= 4%
Verified answer
Let the number = 100
Increase in number = 20% of 100
= [tex] \frac{20}{100} \times 100 \: = \: 20[/tex]
Increased number = 100 + 20 = 120
The resulting number decreased by 20%
[tex]decrease \: in \: number \: = \: \frac{20}{120} \: \times 120 = 24[/tex]
New number = 120 - 24 = 96
Now net decrease = 100 - 96 = 4
[tex]net \: percent \: of \: decrease \: = \: \frac{net \: decrease}{original \: number} \: \times \: 100 [/tex]
[tex] \: \: \: \: \: \: \: \: \: \: = \frac{4}{100} \times 100 \: = 4[/tex]
So your answer is 4%
hope it helps you...