the one who gives the answer for these would be marked as brainiest
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the one who gives the answer for these would be marked as brainiest
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Answer:
(1) Let us take the class mark in each case and create a table containing only the class mark and the frequency .
class mark=(upper class limit+lower class limit)/2
height of the plant(x) frequency(f) fx
5 1 5
15 4 60
25 7 175
35 2 70
45 3 135
55 3 165
Sum of frequency=20
sum of fx=610
mean=610/20=30.5 cm
(3)
(a) you have already marked the answer to this question on the graph with the help of a red cross.
(b)After each year the value of the car increases by 2000 pounds
(c)The 3 1/2 year old mark is the darkened line between 3 and 4
The value of the car will be 3000 pounds.
(2) The modal class interval will be 24<a<26, as this class has the maximum frequency ,i.e., 8
(b)age class mark(x) frequency(f) fx
18<a<20 19 3 57
20<a<22 21 2 42
22<a<24 23 7 161
24<a<26 25 8 200
We are not including the 26<a class because it has 0 frequency
Sum of f=20
sum of fx=460
mean=460/20=23
PLEASE MARK AS BRAINLIEST.