the piece of land increase by 9% every year if the present price is Rupees 1188 1 what was its price 2 years ago?
the piece of land increase by 9% every year if the present price is Rupees 1188 1 what was its price 2 years ago?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
A = p(1+r/100)^n
11881 = p (1+9/100)^2
11881= p(109/100)(109/100)
p= 11881(100*100)/(109*109)
p= 118810000/11881
p= 10000
Answer: Price 2 years ago was Rs. 10000
Step-by-step explanation:
Since we have given that
Present price = 11881
Rate of growth in price = 9%
We need to find the price 2 years ago.
11881 = P(1+0.09)^2
11881=P×1.09^2
11881÷1.1881 = P
P = 10000
Hence, price 2 years ago was Rs. 10000.