The point of intersection of lines 3x + 6y = 9 and 7x – 15y = 2 is
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The point of intersection of lines 3x + 6y = 9 and 7x – 15y = 2 is
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Answer:
Step-by-step explanation:
3x+6y=9-------eq 1
7x-15y=2--------eq 2
x=(2+15y)/7------eq 3
Putting value of X in eq 1,
3{(2+15y)/7}+6y=9
6+45y+42y=63
y= 57/87
y= 19/29
Putting value of Y in eq 3
x=2+15*19/29/7
x=2+285/29/7
x=58+285/29*7
x=343/203
x= 49/29
Answer:
The point of intersection of lines [tex]3x+6y=9[/tex] and [tex]7x-15y=2[/tex] is ( [tex]\frac{49}{29}[/tex],[tex]\frac{57}{87}[/tex])
Step-by-step explanation:
Step 1 of 1:
[tex]3x+6y=9\ \ \ \ \ \ \ \ \ \ ----\ \ eq 1[/tex]
[tex]7x-15y=2\ \ \ \ \ \ \ \ \ \ ----\ \ eq 2[/tex]
[tex]21x+42y=63\ \ \ \ \ \ \ \ \ \ ----\ \ eq 3[/tex]
[tex]21x-45y=6\ \ \ \ \ \ \ \ \ \ ----\ \ eq 4[/tex]
[tex]21x+42y-21x-(-45y)=63-6\\87y=57\\y=\frac{57}{87}[/tex]
Conclusion:
The point of intersection of lines is ( [tex]\frac{49}{29}[/tex],[tex]\frac{57}{87}[/tex])