the population of a town increases by 10% annually if the present population is 22000 find its population year ago. BRAINLISTSOLVE WITH EXPLANATION I WLL GVE U THNKS AND MRK U SA BRAINLIST
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the population of a town increases by 10% annually if the present population is 22000 find its population year ago. BRAINLISTSOLVE WITH EXPLANATION I WLL GVE U THNKS AND MRK U SA BRAINLIST
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Answer:
increased percent=10=0.1 of the population
= 0.1×22000
=2200
now subtract this from the current population=22000-2200
=19800
Let the population a year ago be "x"
Given:
Present population = 22000
Increases per year = 10%
Equation:
x + (x of 10/100) = 22000
Solution:
x + (x of 10/100) = 22000
x + (x × 10/100) = 22000
x + 10x/100 = 22000
x + 10x/100 = 22000
(100x + 10x)/100 = 22000
110x/100 = 22000
110x = 2200000
x = 2200000/110
x = 20000
Therefore:
The population of the town a year ago = 20000 Ans