the present age of man is 3 times that his son. ten years ago, he was 5 times as old as his son, then age of son 3 years later ( in years) is
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the present age of man is 3 times that his son. ten years ago, he was 5 times as old as his son, then age of son 3 years later ( in years) is
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Answer:
x equals to 20
Step-by-step explanation:
Let's the man age to be x.
Ten years ago he was 5 times the age of his son.
Therefore , 3x-10 equals to 5 (x equals to -10)
3x-10 equals to 5x-50
2x equals to 40
Thus 40/2 equals to 20
If the answer is correct pls make me the brainlest
Step-by-step explanation:
[tex]\bf\underline{\underline{\red{Given:-}}}[/tex]
[tex]\bf\underline{\underline{\blue{To\:Find:-}}}[/tex]
[tex]\bf\underline{\underline{\green{Solution:-}}}[/tex]
[tex]\underline{\pink{\bf Case\: 1:-}}[/tex]
The present age of a man is 3 times that of his son.
Let the present age of son be x
Present age of the man = 3x
[tex]\underline{\orange{\bf Case\: 2:-}}[/tex]
Ten years ago:-
Age of son
= Present age of son - 10
= x - 10
Age of man
= Present age of man - 10
= 3x - 10
We have,
Age of son 10 years ago = x - 10
Age of man 10 years ago = 3x - 10
Given, Ten years ago the man was 5 times as old as his son.
So:-
[tex]\rm \implies 3x - 10 = 5(x - 10)[/tex]
[tex]\rm \implies 3x - 10 = 5x - 50[/tex]
[tex]\rm \implies 3x - 5x = -50 + 10[/tex]
[tex]\rm \implies -2x = -40[/tex]
[tex]\rm \implies x = \dfrac{ - 40}{ - 2} [/tex]
[tex]\rm \implies x = 20[/tex]
Present age of son = x = 20
We need to find the age of son 3 years later.
Age of son 3 years later
= Present age of son + 3
= x + 3
= 20 + 3
= 23
[tex] \underline{ \boxed{\rm \purple{\therefore Age \: of \: son \: 3 \: years \: later \: = 23 \: years}}}[/tex]