the present age pf a and b are in the ratio 7:5 and 10 years later their age will be in the ratio 9:7 find the present age
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the present age pf a and b are in the ratio 7:5 and 10 years later their age will be in the ratio 9:7 find the present age
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Given :
To find :
According to the question,
Let the ratio 7x and 5x
[tex] :\implies \sf{ \dfrac{7x + 10}{5x + 10} = \dfrac{9}{7} } [/tex]
[tex] : \implies \sf{7(7x + 10) = 9(5x + 10)}[/tex]
[tex] : \implies \sf{49x + 70 = 45x + 90}[/tex]
[tex] : \implies \sf{49x - 45x = 90 - 70}[/tex]
[tex] : \implies \sf{4x = 20}[/tex]
[tex] : \implies \sf{x = \dfrac{20}{4} }[/tex]
[tex] : \implies { \underline{ \boxed{ \mathfrak \red{x = 5}}}}[/tex]
Given :-
To find :-
Solution:-
let their ages be 7x and 5x
[tex]\bf\dfrac{7x+10}{5x+10}[/tex] = [tex]\bf\dfrac{9}{7}[/tex]
7(7x+10) = 9(5x+10)
49x+70 = 45x + 90
4x = 20
X = [tex]\bf\cancel\dfrac{20}{4}[/tex] = 5x.
hence, their ages are:-