the product of two numbers is 210 and their HCF is 9 if one of the numbers is twice the HCF find the other number
Share
the product of two numbers is 210 and their HCF is 9 if one of the numbers is twice the HCF find the other number
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Step-by-step explanation:
Given:-
the product of two numbers is 210 and their HCF is 9 if one of the numbers is twice the HCF .
To find:-
find the other number?
Solution:-
The product of two numbers =210
HCF of the two numbers=9
one of the numbers =twice the HCF=2(9)=18
Let the other number=X
We know that
LCM×HCF =Product of two numbers
=>LCM×9=210
=>LCM=210/9
=>LCM=70/3
Now,
=>(70/3)×9=18×X
=>630/3=18X
=>210=18X
=>18X=210
=>X=210/18
=>X=70/6
=>35/3
Answer:-
The other number=35/3
Check:-
LCM×HCF=(70/3)×9=(70×9)/3=210
Product of two numbers=210
Verified answer
Step-by-step explanation:
HCF=9
Product of two numbers=210
Let one number be x then, other number will be (2×9)=18
Now,
\begin{gathered}x \times 18 = 210 \\ = > x = \frac{210}{18} \\ = > x = 11.6666\end{gathered}
x×18=210
=>x=
18
210
=>x=11.6666
The second number is 11.6666 .
Please mark my answer the brainliest answer friend.