The rate constant for a first order reaction is 60 s-1. How much time will it
take to reduce 1g of the reactant to 0.0625 g?
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The rate constant for a first order reaction is 60 s-1. How much time will it
take to reduce 1g of the reactant to 0.0625 g?
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a2 = 1 gm
r = 60 S-1
We know for first order reaction
d(a)/ d(t) = r
Thus
d(t) = d(a)/r
= a2-a1 / r
= 1-0.0625 / 60
= 0.015 Sec
Thus time is 0.015 Sec
Answer: 0.046 sec
Explanation: For a first order reaction, the rate law is:
where,
k = rate constant=
t = time taken for decay process= ?
a = initial amount of the reactant = 1 g
a - x = amount left after decay process= 0.0625 g
Putting values in above equation, we get: