the ratio of distances travelled by a body in 1 second, 2seconds and 3 seconds is
Share
the ratio of distances travelled by a body in 1 second, 2seconds and 3 seconds is
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Using s = ut + 0.5at^2 where u = 0 and assuming a = 9.8m/s^2, in the first second the body will fall 0.5 x 9.8 x 1^2 = 4.9m
In 2 seconds, the body will fall 0.5 x 9.8 x 2^2 = 19.6m
In 3 seconds, the body will fall 0.5 x 9.8 x 3^2 = 44.1m
So, in the first second, 4.9m, in the second second, (19.9 - 4.9) = 14.7m and in the third second, (44.1 - 19.6) = 24.5m
4.9:14.7:24.5, or 1:3:5