The ratio of males to females in a committee of 48 members is 3:1. How many more ladies be added to the committee so that the ratio of males to females may be 9:5
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The ratio of males to females in a committee of 48 members is 3:1. How many more ladies be added to the committee so that the ratio of males to females may be 9:5
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Verified answer
Answer:
8
Solution:
Here,
It is given that ,
The ratio of males to females in a committee of 48 members is 3:1.
Thus,
Let the no. of males = 3x
And the no. of females = x
According to the question ;
=> 3x + x = 48
=> 4x = 48
=> x = 48/4
=> x = 12
Thus,
No. of males = 3x = 3•12 = 36
No. of females = x = 12
Now,
Let the no. of more ladies to be added be y , so that the ratio become 9:5.
Thus,
=> 36:(12 + y) = 9:5
=> 36/(12 + y) = 9/5
=> 36•5 = 9•(12 + y)
=> 12 + y = 36•5/9
=> 12 + y = 20
=> y = 20 - 12
=> y = 8
Hence,
The required answer is 8 .
Answer:
Step-by-step explanation:
Given
To find
Solution
Total numbers of members in a committee = 48
Ratio of males to females = 3 : 1
Sum of terms of ratio = 3 + 1 = 4
Number of males = 3/4 × 48
Number of males = 36.
Number of females = (48 - 36) = 12.
Let x be the number of females be added to the committee.
Then, number of females = 12 + x
ATP:
Hence, more 8 ladies must be added to the committee so that the ratio of males to females will be 9 : 5.