The reactance of a capacitance at 50 Hz is 5 ohm. If the frequency is increased to 100 Hz, the new reactance is
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The reactance of a capacitance at 50 Hz is 5 ohm. If the frequency is increased to 100 Hz, the new reactance is
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Explanation:
Capacitive reactance
Xc = 1/2πf
Therefore XC1/XC2 = 2πf2/2πf1
= 20/XC2 =100/50
= XC2 = 10
the new reactance is 10 OHMS
2.5ohm
Explanation :
Reactance : The measure of opposition to current flow offeredd by a material is known as reactance, denoted by R. The resistance offered to ac currents only bby inductors and capacitors is the reactance, denoted by X.
For capacitor,[tex]XC = 1 / 2πf[/tex]
As given, XC1 = 5ohm
frequency f1 = 50Hz
XC2 = ?
frequency f2 = 100Hz
Applying the formula,
[tex]XC1 / XC2 = 2πf2 / 2πf1[/tex]
[tex]5 / XC2 = 100 / 50[/tex]
[tex]5 / XC2 = 2[/tex]
[tex]XC2 = 5 / 2[/tex]
[tex]XC2 = 2.5 ohm[/tex]
From the formula we can predict that as the frequency increases the reactance decreases as they are inversely proportional to each other.