The sides of a triangle are 45cm, 39cm, and 42 cm, find its semiperimeter
Share
The sides of a triangle are 45cm, 39cm, and 42 cm, find its semiperimeter
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Sides of a triangle are 45 cm, 39 cm and 42 cm. Here, a = 45cm, b = 39cm, c = 42cm Semi perimeter of triangle = s = (1/2) (a + b + c) = (1/2) (45 + 39 + 42) = 126/2 = 63 Area of a triangle ∴ The area of the triangle is 756 sq.
Step-by-step explanation:
Hey
a = 42 cm
b = 39cm
c = 45cm .
So ,
s = a + b + c / 2
s = 42 + 39 + 45 / 2
s = 126 / 2
s = 63 .
Now ,
area = \sqrt{s(s - a)(s - b)(s - c)}area=
s(s−a)(s−b)(s−c)
= \sqrt{63(63 - 42)(63 - 39)(63 - 45)}=
63(63−42)(63−39)(63−45)
= \sqrt{63 \times 21 \times 24 \times 18}=
63×21×24×18
= \sqrt{9 \times 7 \times 7 \times 3 \times 6 \times 4 \times 6 \times 3}=
9×7×7×3×6×4×6×3
= 3 \times 7 \times 3 \times 6 \times 2=3×7×3×6×2
= 108 \times 7=108×7
= 756=756
So , area = 756 cm²