The sides of a triangle are in the form of consecutive even integer .If it's perimeter is 48 cm ,find the measure of each
The sides of a triangle are in the form of consecutive even integer .If it's perimeter is 48 cm ,find the measure of each
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▶ Given :
↪ The sides of a triangle are in the form of consecutive even integer.
↪ Let the sides be x, x + 1, x + 2.
↪ Perimeter of the triangle = 48 cm
▶ To Find : The measure of each sides.
▶ Solution :
↪ Perimeter of a triangle = Sum of all the sides
↪ 48 = x + x + 1 + x + 2
↪ 3x + 3 = 48
↪ 3x = 48 - 3
↪ 3x = 45
↪ x = 15
↪ Sides of the triangle are 15, 16 and 17.
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Simple
=> To find = Measure of each side
So ,
Let sides be x , x + 1 and x + 2
As we know Perimeter means sum of all sides
So ,
According to Question
48 = x + x + 1 + x + 2
48 = 3 x + 3
48 - 3 = 3 x
45 = 3 x
x = 45 / 3
x = 15
So ,
One side = 15 cm
Second side = 15 + 1
= 16 cm
Third side = 15 + 2
= 17 cm
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