The smallest number which when divided
by 20, 25, 35 and 40 leaves a remainder of
14, 19, 29 and 34 respectively, is
(A) 1394
(B) 1404
(C) 1664
(D) 1406
Plz give the explanation step by step
Share
The smallest number which when divided
by 20, 25, 35 and 40 leaves a remainder of
14, 19, 29 and 34 respectively, is
(A) 1394
(B) 1404
(C) 1664
(D) 1406
Plz give the explanation step by step
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
First follow me than I will give you a correct answer with explanation
What is the smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29, 34 respectively?
This is a question of multiple divisors with multiple remainders.
Although the remainders seem different, but they are the same when we take their negative counterparts.
R[N/20]=14R[N/20]=14 or (−6)(−6)
R[N/25]=19R[N/25]=19 or (−6)(−6)
R[N/35]=29R[N/35]=29 or (−6)(−6)
R[N/40]=34R[N/40]=34 or (−6)(−6)
So, we can see NN leaves the same remainder (-6) when divided by 20, 25, 35 or 40.
So, N=LCM(20,25,35,40)+(−6)N=LCM(20,25,35,40)+(−6)
Or, N=1394N=1394 (Answer)
Like my answer
Follow me
Mark me as brainlist
Hope it help