the sum here angles of a triangle are 11x-14x+15and 20x-9.find the measure of all the angles of triangle
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the sum here angles of a triangle are 11x-14x+15and 20x-9.find the measure of all the angles of triangle
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Answer:
Given measure of three angles of a triangle are 11x-1,4x+15 and 20x-9. Recall that sum of the angles in a triangle is 180° Hence (11x-1) + (4x+15) + (20x - 9) = 180° ⇒ 35x + 5 = 180° ⇒ 35x = 175° ∴ x = 5° Hence (11x − 1) = 11(5) - 1 = 54° (4x + 15) = 4(5) + 15 = 35° (20x − 9) = 20(5) − 9 = 91° The three angles of the given triangle are 54° ,35° and91°
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