the sum of the digits of a two-digit number is 10 if the number formed by reversing the digit is less than the original number by 18 find the original number
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the sum of the digits of a two-digit number is 10 if the number formed by reversing the digit is less than the original number by 18 find the original number
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Given sum of two digits=10
X+Y=10 ...........eq-1
number formed by reversing the digits is 18 less than the original.
10Y+X+18=10X+Y
=>9X-9Y=18 ..........eq-2
solving eq-1 and 2
X=6 and Y=4