The sum of the digits of a two-digit number is 13. If 9 is added to the number, the digits are reversed. Then the original number is
(I want the answer in one variable)
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The sum of the digits of a two-digit number is 13. If 9 is added to the number, the digits are reversed. Then the original number is
(I want the answer in one variable)
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Step-by-step explanation:
let,
no.=10x+y
so,
10x+y+9=10y+x
10x-x+y-10y= -9
9x-9y= -9
9(x-y)= -9
x-y= -9/9
x-y= -1
it is given that,
x+y=13 so,
x+y+x-y=13+(-1)
2x=13-1
2x=12
x=12/2
x=6
and x+y=13
6+y=13
y=13-6=7
so; number is 10x+y=10×6+7=60+7=67
Answer:
67
Step-by-step explanation:
Let the number be written as = 10x + y
sum of two digit number is =
=> x + y = 13 ....... (1)
9 is added to the number
=> 10x + y + 9 = 10y + x
=> 9x - 9y = -9
=> x - y = -1...... (2)
from equation (1) and (2) we get
=> 2x = 12
=> x = 6
put x = 6 in equation (1)
=> 6 + y = 13
=> y = 7
the original number is = 10x + y
=> 10 (6) + 7
=> 67 = ANSWER