the sum of three consecutive arithematic sequence is 30 and their product is 910.find the terms
plz tell the way also
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the sum of three consecutive arithematic sequence is 30 and their product is 910.find the terms
plz tell the way also
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Answer:
Answer is given below
Step-by-step explanation:
Let the terms be (a-d) (a) and (a+d)
Sum =30
a-d+a+a+d=30
3a=30
a=10
Given product =910
(a-d)a(a+d)=910
(a^2-d^2)a=910
But, a=10
(10a^2 - d^2)*10=910
100-d^2=91
100-91=d^2
d^2=9
d= +3
So,the numbers are a-d=10+3=13
a=10
a+d=10+(3)
=10-3
=7
a-d=10-(+3)
=10-3
=7
a=10
a+d=10+3
=13
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