The sum of three consecutive integers is 24, then the least integer is
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The sum of three consecutive integers is 24, then the least integer is
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Answer:
least integer=7
Step-by-step explanation:
let the three consecutive integers be x, x+1, x+2
x+x+1+x+2=24
3x+3=24
3x=24-3
3x=21
x=21/3
x=7
x+1=7+1=8
x+2=7+2=9
The sum of three consecutive integers is 24.
The least number.
Let the three integers be x, x+1, x+2.
According to the question,
[tex]\large\Longrightarrow{\sf{x+x+1+x+2=24}}[/tex]
[tex]\large\Longrightarrow{\sf{3x+3=24}}[/tex]
[tex]\large\Longrightarrow{\sf{3x=24-3}}[/tex]
[tex]\large\Longrightarrow{\sf{x=\huge\frac{21}{3}}}[/tex]
[tex]\large\therefore\boxed{\sf{x=7}}[/tex]
The integers are:-
x = 7
(x + 1) = (7 + 1) = 8
(x + 2) = (7 + 2) = 9
[tex]\large\red\therefore\boxed{\sf{\red{The\: least\: integer \:is\: 7.}}}[/tex]