the sum of three consecutive multiples of 11 is 363 find these multiples
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the sum of three consecutive multiples of 11 is 363 find these multiples
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Answer:
one be n+1, n+2, n+3
then,
3n +6= 363
3n = 357
n = 357/3
n = 119
no. are - 120,121,122
Answer:
110 , 121 , 132
Step-by-step explanation:
Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22
Their sum is 363
11x+11x+11+11x+22=363
33x+33=363
33x=363−33
33x=330
x= 33/330
x=10
First multiple =11x=11×10=110
Second multiple =11x+11=110+11=121
Third multiple =11x+22=110+22=132