the sum of two digit number and the number formed by interchanging its digits is 110 if 10 is subtracted from the first number the new number is 4 more than five times of the sum of digits is the first number find the first number
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the sum of two digit number and the number formed by interchanging its digits is 110 if 10 is subtracted from the first number the new number is 4 more than five times of the sum of digits is the first number find the first number
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Step-by-step explanation:
Here is your solution
Let the digit at ones place = y
Let the digit at tens place = x
original number = 10x + y
Number formed by reversing the digits =10y + x
On adding original number and Reversed number.
10x+y+10y+x = 110
11x + 11y = 110
11 (x + y ) = 110
x + y = 10
x = 10 - y ................................................. (1)
on subtracting 10 from the original number , we get = 10x + y -10
and
4 more than 5 times the sum of digits = 5(x + y) + 4
A/q
10x + y -10 = 5(x + y) + 4
10x + y -10 = 5x +5y + 4
10x -5x + y -5y = 10 +4
5x - 4y = 14.................................................. (2)
putting the value of x in equation (2)
5x - 4y = 14
5×(10-y) - 4y = 14
50-5y-4y =14
-9y = 14 -50
-9y = -36
y = 4
Now
x = 10-y
x = 10 - 4
x = 6
original number or first numbe = 10x + y = 10×6+4 = 64
Hope it helps you
Answer:
64 is the answer
Step-by-step explanation:
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