The sum of zeroes of a quadratic polynomial 6x2-7x-3 will be
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Let 6x2 - 7x-3 be p(x) =0
so,6x2 - 7x-3 =0
6x2 - (9-2) x -3
6x2 - 9x + 2x -3
(6x2 - 9x)(2x-3)
3x(2x-3) +1 (2x-3)
(3x +1) (2x -3) = 0
⇒ 3x +1 = 0
⇒ 2x -3 = 0
⇒ x =3/2
⇒ x = - 1/3
sum of zeroes = -1/3 + 3/2 =7/6 = -b/a
product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a
Step-by-step explanation:
hope it's helpful