the sum the age's of A and B is 46 . five years ago the age of B was twice that of A .find A's age.
the sum the age's of A and B is 46 . five years ago the age of B was twice that of A .find A's age.
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Answer:
Step-by-step explanation:
Let A 's age = x
And B 's age =y
5 year ago , A 's age = x -5
B ' s age = y- 5
A to q
x + y = 46..........(1)
2nd condition ( y- 5) = 2 (x -5)
y- 5 = 2x -10
y = 2x -5...........(2)
By (1) put the value of y in (1)
x + 2x -5 =46
3x = 46 +5 = 51
X = 51/3 = 17
So A 's age = 17 year
simple and easy soln
hope it will help you.........
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