The sum to n terms of an arithmetic progression?
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The sum to n terms of an arithmetic progression?
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Formula for sum of n terms = ( n/2) ( 2a + ( n- 1 ) d )....
n = Number of terms
a = first term
d = common difference. .
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Verified answer
Sum = (n/2)*(a+{n-1}d)Where, n = number of terms
a = first term
d = common difference.