the surface tension of soap solution is 25×10^-3 NM^-1. the excess pressure inside a soap bubble of diameter 1 cm is
the surface tension of soap solution is 25×10^-3 NM^-1. the excess pressure inside a soap bubble of diameter 1 cm is
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The excess pressure is calculated as ΔP=
r
4T
ΔP=
0.5×10
−2
4×25×10
−3
=20N/m
2
1Pa=1N/m
2
⇒ΔP=20Pa
Option C is correct.