The value of K for which quadratic
kx² + 2kx-(k-1) has equal root
is
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The value of K for which quadratic
kx² + 2kx-(k-1) has equal root
is
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Step-by-step explanation:
kx²+2kc-(k-1)=0
use the formula b2-4ac OK friend this is urs answer
ANSWER:
★ QUADRATIC RESOLUTION ★
Given equation :
kx² - kx + 1 = 0
For equal roots :
D = 0
k² - 4( k ) = 0
k² = 4k
k = 4
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Please mark my answer Brainliest answer.