The value of 2log2+log3log48−log4 is
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Answer
Solution :
a)log510⋅log210+(log210)2
log10102log10.210+...
(1−log2)(1+log2)+(log2)2
1−(log2)2+(log2)2=1
b)2log2+log3log48−log4=log4+log2log48−log4
log4⋅3log(484)=log12log12=1
c)−log5log3(915)12
−log5log3325⋅2
−log