The velocity of the maximum projectile is √3by2times its initial velocity of projection (u). its range on the horizontal plane is.
please solve this question in details plzzzzzzzzzzzzzzzzzz
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The velocity of the maximum projectile is √3by2times its initial velocity of projection (u). its range on the horizontal plane is.
please solve this question in details plzzzzzzzzzzzzzzzzzz
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here u. cos theta = root3/2 x u... cos theta = root/2...theta = 30°...range = (u^2. sin 2theta)/g = (u^2.sin 60)/g = (u^2.root3/2)/g.