the volume occupied by 4 grams of H2 at STP
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the volume occupied by 4 grams of H2 at STP
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Answer:
PV= nRT
we want to find volume at stp
Therefore T=273k,p=1atm,n=2,R=8.314
V= n×R×T /P
V= 2×8.314×273/1
V=4539.44 ml.
Number of moles of Hydrogen (H₂) = given weight/molecular weight = 4/2 = 2
We know 1 mole of any gas at STP occupies 22.4 litres of volume
So, 2 moles of a gas occupies 44.8 litres of volume
Therefore, 4g of H₂ gas at STP occupies 44.8 litres of volume.
Hope it helps!!