The volume of a drop of rain was found to be 0.448ml at N.T.P. how many molecules of water and number of atom of hydrogen are present in this drop
The volume of a drop of rain was found to be 0.448ml at N.T.P. how many molecules of water and number of atom of hydrogen are present in this drop
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Answer:
taking the density of water=1g/cm³or 1g/ml
mass=density×volume
mass of water=1×0.448=0.448g
Mollar mass of water=h20×2×1=18g/mol
moles of water=0.448/18=0.0249
avogadro's number=6.022×10^23
Number of molecules of water=6.022×10^23×0.0249=1.5×10^22
1 molecules of water has 2 hydrogen atoms
no. of hydrogen atoms =2×1.5×10^22=3×10^22