The weight of a body of mass 10kg on the surface of a celestial body is 80N. Calculate the value of ‘g’ on its surface.
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The weight of a body of mass 10kg on the surface of a celestial body is 80N. Calculate the value of ‘g’ on its surface.
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As per the provided information in the given question, we have been provided that the weight of a body of mass 10kg on the surface of a celestial body is 80N. And, we have been asked to calculate the acceleration due to gravity on the surface of that celestial body denoted as g.
In order to tackle this question, we must know th formula which is used to calculate the weight. Weight is calculated by finding the product of mass and acceleration due to gravity. As acceleration due to gravity changes place to place and isn't constant so weight also changes place to place. And, mass is constant, it doesn't change from place to place. SI unit of Weight is "Newton". Now, we know that,
[tex] \quad \quad \star \; \underline{\boxed{\mathfrak{\pmb { W = mg }}}} \\ [/tex]
Substitute the values.
[tex] \dashrightarrow \quad \sf {80 = 10g } \\ \\ \dashrightarrow \quad \sf {\cancel{\dfrac{80}{10}} = g }\\ \\ \dashrightarrow \quad\underline{\boxed{\sf{\red{ \pmb{ 8 }\; \pmb{ ms}^{\pmb{ -2}} = \pmb{ g}}}}} [/tex]
∴ The value of ‘g’ on its surface is 8 m/s².