Three coins are tossed simultaneously 200 times
Find the probability of getting at most one head
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Three coins are tossed simultaneously 200 times
Find the probability of getting at most one head
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Given that total number of times coin is tossed = 200.
Let A be the probability of getting atmost 1 head.
⇒ n(A) = No heads + 1 head
= 28 + 77
= 105.
Therefore, required probability P(A) = n(A)/n(S) = 105/200.
Hope this helps!
if 77 head then 23 + 100
if 23 head then 77 + 100
then 172 heads