three consecutive integers add up to 51.
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Answer:
Let the first integer be m
Let the second integer be m+1
Let the third integer be m+2
ATQ
m+m+1+m+2 = 51
3m +3 = 51
3m = 51-3
3m = 48
m = 48/3
m = 16
therefore, first integer = m = 16
second integer = m+1 = 16+1 = 17
third integer = m+2 = 16+2 = 18
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