Air contains O2 and N2 in the ratio of 1: 4. Calculate the ratio of solubilities in terms of mole fraction of Oz and Nz dissolved in
water at Atmospheric pressure and room temperature at which Henry's Constant for O2 and N2 are 3.30 x 10 torr 6.60 x
10/torr respectively.
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Answer:
Given,
The ratio of the O
2
&N
2
=1:4
So, pO
2
=K
H
XO
2
1=K
H
2
XO
2
XO
2
=
K
H
2
1
pN
2
=K
H
XN
2
1=KH
N
2
XN
2
XN
2
=
K
H
N
2
1
Thus the ratio is:
K
H
N
2
1
K
H
2
1
XO
2
:XN
2
=
3.33×10
7
1
:
6.6×10
7
1
1:2