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# HridayAg0102
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= 3n²/2 + 13n/2
First term, a = 8
Sum of two terms = 19
2nd term = 19-8 = 11
Thus,
Common difference, d = 11-3 = 8
∴ 25th term = (8 + (25 -1)×3) = 80
Alternative method:
nth term of an A.P. = (Sum of nth term ) - [Sum of (n-1)th term]
25th term = (Sum of 25 terms) - ( Sum of 24 terms)
=(3×(25)²/2 +(13×25)/2) - ( 3×(24)²/2 + (13×24)/2)
= 1100 - 1020
= 80
Hence, the 25th Term is = 80
HOPE IT HELPS ^_^