T.S.A. of cuboid A=(lb+bh+ hl) make; a) "1" as a subject (b) "b" as a subject
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T.S.A. of cuboid A=(lb+bh+ hl) make; a) "1" as a subject (b) "b" as a subject
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Answer:
T.S.A of cuboid = 2(lb+bh+hl)
A÷2 = lb+bh+hl
A÷2 = l(b+h) + bh
A÷2-bh= l(b+h)
(A÷2-bh)/b+h = l (l as subject)
similarly
A÷2 = lb+bh+hl
A÷2 -hl = (l+h)b
(A÷2-hl)/l+h = b (b as subject).
But as the question says
If
A = (lb+bh+hl)
then
A = l(b+h) +bh
A-bh = l(b+h)
(A-bh)/b+h = l (l as subject)
similarly
if
A = (lb+bh+hl)
A-hl = (l+h)b
(A-hl)/(l+h) = b (b as subject)...