Two blocks of masses 2 kg and 1 kg are in contact with each other on a
horizontal frictionless table. When a horizontal force of 3.0 N is applied to
the block of mass 2 kg, find the value of the force of contact between the two
blocks.
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Two blocks of masses 2 kg and 1 kg are in contact with each other on a
horizontal frictionless table. When a horizontal force of 3.0 N is applied to
the block of mass 2 kg, find the value of the force of contact between the two
blocks.
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Answer:
The value of force contact between two blocks is 1N.
Answer:
The value of force contact between two blocks is 1N
Explanation:
The 3.0 N force will cause the total 3 kg to accelerate. The value of that acceleration will be
a = F/m = 3 N / 3kg = 1 m/s^2
Since the 1 kg block is accelerating at 1 m/s^2, the force on it must be
F = m*a = 1 kg*1 m/s^2 = 1 N
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