Two buildings 22 m and 30 m high stand up right on a ground. If they are 15 m apart, the distance between their tops is -----------
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Two buildings 22 m and 30 m high stand up right on a ground. If they are 15 m apart, the distance between their tops is -----------
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Answer:
17m
Step-by-step explanation:
now the height of first building AB= 22m
height of second building DC = 30 m
thus, the difference between their hights (AE) = 30-22 = 8
the horizontal distance between two buildings (BC) = 15m
ABCE form a rectangle, thus AE = BC = 15m
now, triangle AED is right angle triangle with angles E=90°
using Pythagoras theorem ,
AD^2 = (AE^2) + (DE^2)
= (15^2) + (8^2)
= 225 + 64
= 289
AD = √289
= 17m