Two Complementary angles are such that 2 times the measure of 1 is equal to 3 times the measure of the other. The measure of smaller angle is...?
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Two Complementary angles are such that 2 times the measure of 1 is equal to 3 times the measure of
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Answer:
Let the measure of one angle be X
then, the measure of its complement is 90° - X
ATQ,
2x = 3(90°-x)
= 2x = 270° -3x
= 2x+3x = 270°
= 5x = 270°
= X= 54°
=> 90°-x
=> 90°-54°
=> 36°
Hence, the measure of smaller angle is 36°.
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Two Complementary angles are such that 2 times the measure of 1 is equal to 3 times the measure of the other. The measure of smaller angle is...?
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Let the measure of one angle be X
Let the measure of one angle be X then, the measure of its complement is 90° - X
ATQ,
2x = 3(90°-x)
= 2x = 270° -3x
= 2x+3x = 270°
= 5x = 270°
= X= 54°
=> 90°-x
=> 90°-54°
=> 36°
Hence, the measure of smaller angle is 36°.
Thanks..