two different dice are tossed together. find the probability that the product of the two number on the top of the dice is 6.
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two different dice are tossed together. find the probability that the product of the two number on the top of the dice is 6.
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Solution: Two dices are thrown no probable chances are
(1, 1); (1, 2); (1, 3); (1, 4); (1, 5); (1, 6)
(2, 1); (2, 2); (2, 3); (2, 4); (2, 5); (2, 6)
(3, 1); (3, 2); (3, 3); (3, 4); (3, 5); (3, 6)
(4, 1); (4, 2); (4, 3); (4, 4); (4, 5); (4, 6)
(5, 1); (5, 2); (5, 3); (5, 4); (5, 5); (5, 6)
(6, 1); (6, 2); (6, 3); (6, 4); (6, 5); (6, 6)
How many sets possible? Yeah it's 36.
Out of these 36 sets, we know product should be 6.
In what cases 6 can be product?
→ 6 × 1, 1 × 6, 2 × 3, 3 × 2
→ (6, 1); (1, 6); (2, 3); (3, 2)
How many time these sets came? Yeah it's 4.
Probability = 4/36 = 1/9
Answer is 1/9
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Answer:
Step-by-step explanation:
Given :-
Two different dice are tossed together.
To Find :-
The probability
Solution :-
Two dice are thrown, the outcome is listed as
1 ; 2 ; 3 ; 4 ; 5 ; 1
1 (1, 1); (1, 2); (1, 3); (1, 4); (1, 5); (1, 6)
2 (2, 1); (2, 2); (2, 3); (2, 4); (2, 5); (2, 6)
3 (3, 1); (3, 2); (3, 3); (3, 4); (3, 5); (3, 6)
4 (4, 1); (4, 2); (4, 3); (4, 4); (4, 5); (4, 6)
5 (5, 1); (5, 2); (5, 3); (5, 4); (5, 5); (5, 6)
6 (6, 1); (6, 2); (6, 3); (6, 4); (6, 5); (6, 6)
Total Number of possible outcomes = 36
The favourable outcome is denoted by E and are (1, 6), (2, 3), (3, 2) and (6, 1)
Number of favourable outcomes = 4
P E =
P E =
P E =
Hence, the probability is 1/9.