Two interior angles on the same side of the transversal measure (a-6) degree and (5a-6) degree. Find the measure of each angle.
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Two interior angles on the same side of the transversal measure (a-6) degree and (5a-6) degree. Find the measure of each angle.
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if two lines are parallel
sum of interior angles on same side of transversal are supplementary
(a-6) + (5a-6) = 180
6a - 12 = 180
6a = 180 + 12
6a = 192
a = 192 / 6
a = 32
therefore,
first angle = a-6 = 32 - 6 = 26
second angle = 5a-6 = 5×32 - 6 = 160 - 6 = 154