Two numbers are chosen from 1 to 5. the probability for the 2 numbers to be consecutive is?
Can we do this by multiplication?
If not why?can u pls explain this.
i will mark u the brainliest if u explain this to me propoperly.
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Two numbers are chosen from 1 to 5. the probability for the 2 numbers to be consecutive is?
Can we do this by multiplication?
If not why?can u pls explain this.
i will mark u the brainliest if u explain this to me propoperly.
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Answer:
No
Step-by-step explanation:
We can do it in table form only
Answer: No, because it's not possible to do directly because their is the condition of two consecutive numbers and they are in the form of increasing order always so, we have to apply the formula for this,
Hope you got it.
BTW here's the solution
Answer: 2/5
Step-by-step explanation:
Dear student,
Total no. of digits - 1, 2, 3, 4, 5
Numbers of ways of selecting 2 digits out of the 5 digits above
n!/(r!/(n-r)!)
here n is total no.
r is number of selection
so, 5!/(2!/(5-2)!)
after solving 20/2 = 10
.. Favorable ways of selecting 2 consecutive numbers
= (1,2) (2,3) (3,4) (4,5)
hence there are 4 such possibility
so,
Probability = favourable cases/Total no. of ways
= 4/10
= 2/5
so, here your answer with explanation..
regards,