Two numbers are in ratio 5 : 8, If their difference is 48, then the smallest numbers is
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Two numbers are in ratio 5 : 8, If their difference is 48, then the smallest numbers is
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Let, both of the numbers be 5x and 8x.
B/c,
5x-8x= 48
-3x= 48
X= 48/3
X= 16
therefore the smaller number is,
5 x = 90
Let assume be any constant term =X so, the number be 5X and 8X ( according to the ratio given).
Now second condition, Difference =48.
Here are two option either substract 5X -8X or 8X -5X both are right and okay.
Let suppose we substract 5X-8X=48
-3X=48
X=-16
So, the number will be -80 and - 128. The smaller number will be -128 answer okay. Because when we count the smaller number in negative term which is larger one that is smaller one number.
Now, 8X-5X=48
3X=48
X=16
So, the number will be 80 and 128. The smaller number will be 80 answer.
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