Two numbers are in the ratio 3 : 5, if their sum is 48 then the numbers are:
(a) 8,40
(b) 12,36
(c) 18,30
(d) 30,18
Option 5
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Two numbers are in the ratio 3 : 5, if their sum is 48 then the numbers are:
(a) 8,40
(b) 12,36
(c) 18,30
(d) 30,18
Option 5
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Step-by-step explanation:
3x+5x=48
8x=48
x=48/8
x=6
3x=3×6=18
5x=5×5=30
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Answer:
Two numbers are in the ratio [tex]3:5[/tex], if their sum is 48 then the numbers are the value of the option(c) 18,30
Step-by-step explanation:
We have a ratio of two numbers as 3:5 and the sum of those two numbers is 48 and now we have to find those numbers.
Step 1 of 2
Since the numbers are in ratio so there must be one common factor by which they can be divided. Let us assume that factor [tex]x[/tex] then
[tex]3x+5x=48[/tex]
⇒[tex]8x=48\\[/tex]
⇒[tex]x=6[/tex]
So that common factor is 6
Step 2 of 2
Then by multiplying this common factor with the ratio we will get the original numbers. So
[tex]3*6=18\\and5*6=30[/tex]
And these numbers are in option (c)
Hence the two umbers are contained in option(c) 18,30