Two oxide of metal contain 80% and 88.8% of the metal respectively.Show that the data in agreement with multiple proportion.
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Two oxide of metal contain 80% and 88.8% of the metal respectively.Show that the data in agreement with multiple proportion.
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Answer:
Given that ,in higher oxide 80% metal is true.
wt. of metal=
100
80
×0.8
=0.64gm
wt. of oxygen=0.16gm
in lower oxide,
wt. of metal will be same as that of higher oxidation state(+2)
wt. of oxygen=(72−0.64)=0.08g
so,ratio of weight of O
2
& meals in two oxide is 0.16:0.08=2:1.
1000ml of 0.75 M HCl = 0.75 mol
So, 25 ml of HCl will contain HCl = 0.75×25/1000 = 0.01875
2 mol of HCl reacts with 1 mol of CaCO
3
So, 0.01875 mol of HCl will react with
2
1
× 0.01875 = 0.009375 mol
Molar mass of CaCO
3
= 100 g
Hence, the mass of 0.009375 mol of CaCO
3
= no. of moles × molar mass$$
0.009375 ×100