Two taps together can fill the tank in 6 hours while one of the tap can fill it alone in 8 hours, if both the taps are open in the tank and after 1 hour tap B is closed then how much more time A will take to fill the tank. Pls i need urgent !
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Step-by-step explanation:
Let x be the time of A tap
x+5 be the time of B tap
As per the statement the equation becomes,
x
1
+
x+5
1
=
6
1
Multiplying x(x+5) on both sides to eliminate the denominator.
6x+30+6x=x
2
+5x
x
2
−7x−30=0
On factoring, we get
(x−10)(x+3)=0
x=10 or −3
A tap to fill the tank separately is 10 hours